Program example using void-functions

Problem example:

Write a program that converts from 24-hour notation to 12-hour notation.
For example, it should convert 14:25 to 2:25 PM. The input is given as two integers.
There should be at least three functions, one for input, one to do the conversion, and one
for output. Record the AM/PM information as a value of type char, ’A’ for AM and ’P’
for PM. Thus, the function for doing the conversions will have a call-by-reference formal
parameter of type char to record whether it is AM or PM. (The function will have other
parameters as well.) Include a loop that lets the user repeat this computation for new
input values again and again until the user says he or she wants to end the program.


#include <iostream>
using namespace std;

void input(int& hours, int& minutes);
void output(int& hours, int& minutes, char& type);
void convert(int& hours, int& minutes, char& type);

int main()
{
  int hours, minutes;
  char type, ans;

do
  {
    input(hours, minutes);
    convert(hours, minutes, type);
    output(hours, minutes, type);

    cout <<"Wanna do it again? (y/n):\n";
    cin >> ans;
  }
 while (ans == 'y' || ans == 'Y');

 return 0;
}

void input(int& hours, int& minutes)
{

  while (hours > 23 && minutes > 59);
  {
  cout << "Enter the hours for the 24 hour time format:\n";
  cin >> hours;
  cout << "Enter the minutes for the 24 hour time format:\n";
  cin >> minutes;
  }
}

void output(int& hours, int& minutes, char& type)
{
  cout << "The time converted to 12 hour format is:" << hours << ":";
  cout.width(2);
  cout.fill('0');
  cout << minutes;

  if (type == 'P')
    {
      cout << "P.M." << endl;
    }
     
  else
    {
      cout << "A.M." << endl;
    }
}
 

void convert (int& hours, int& minutes, char& type)
{

  if(hours < 12)
    {
       type = 'A';
    }
  else if (hours > 12)
    {
      hours = hours - 12;
      type = 'P';
    }
  else
    {
      type = 'P';
    }
}